Fissioning LED test run.

Airwalker16 said:

Positive gets resistor and always goes to middle pole. The negative goes to the outer pole, what side you choose determines which way will dim it to 0%.
And yes there's another resistor underneath, because those were 5.6K, so I had to use 2 to get close to 10K.(11.2)

Also, I can't remember if you're wiring 2 drivers to one pot, the pot has to be a 50K ohm pot, so I think the resistor is a 5K. I thought you doubled up on them for a second but that doesn't seem right.

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Boatguy said:

Just checked my order history. I used a 100k pot with no resistor. I think you are right about 2 drivers needing a 50k

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Airwalker16 said:

I know for sure 2 drivers needs a 50K pot. Just unsure what resistor value you need

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Boatguy said:

i think none. Could be wrong though

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Airwalker16 said:

Positive gets resistor and always goes to middle pole. The negative goes to the outer pole, what side you choose determines which way will dim it to 0%.
And yes there's another resistor underneath, because those were 5.6K, so I had to use 2 to get close to 10K.(11.2)

Also, I can't remember if you're wiring 2 drivers to one pot, the pot has to be a 50K ohm pot, so I think the resistor is a 5K. I thought you doubled up on them for a second but that doesn't seem right.

Click to expand...

Boatguy said:

Poles just dictate which direction turn dims. 100k pot is all you need for one driver, no resistor. 2 driver setup is where i am not sure

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