Fentanyl conversion

A mole is 6.022 * 10^23 molecules, which will have a mass in grams equal to the compounds molecular weight. Molecular weights are easily obtained by looking them up. The liter of solvent is probably what the NPP would be dissolved in prior to the reaction with aniline.
 
hey mre, i had always thought a mole was 6.022 x 10 to the -23 power, am i wrong about this?? it's like the one formula i remembered from chem class in jr year..
oh, that and the speed of sound at sea level..
 
Nope, if it was ten to the -23 you'd end up with a tiny fraction of a particle. Still you almost had it right, at least you remembered something from chem class.
 
And a MMOL is a MOL divided by 1000...correct?

10 mmole of NPP is dissolved in a minimal volume of aniline (about 5-6 ml)

What is 10 MMOL of
N-Phenyl-Imine??? (the NPP) I looked up the molecular weight but can not fine. So how much would I add to the 6 ml of Aniline?


ALSO! Clear out your inbox so I can message you :P
 
Nope, if it was ten to the -23 you'd end up with a tiny fraction of a particle. Still you almost had it right, at least you remembered something from chem class.

yeah, i wasn't a real big fan of chemistry.. i was a science geek in high school, but always hated math class, and to me chem was way more of a math then a science...
 
The imine is the condensation product of the NPP and analine. Condensation is the loss of a water molecule so the product will have a molecular weight equal to the molecular weight of the reactants minus 18 (the MW of water). There's room in my inbox, I cleared some the other day.
 
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