how does that work? is there a capacitor in the driver circuit or cob itself?
I meant to say, the typical vf of the led board is 46vf.
depends on the current
If the current is at or below the maximum for that part of the curve it will work?
Low voltage cutout. Below rated volts will not work but blink or not light at all.
What I'm confused about is the statement that I've heard here more than once it with the constant voltage driver if one of your chips blows then all the extra Amps get sent to the remaining chips .
That statement is utter nonsense. The current through any LED is ENTIRELY dependent on the voltage applied and the LED junction temperature. If the voltage is constant, the current though the LED device is constant as well, barring temp shifts. Anything in parallel with it is irrelevant, unless the voltage supply is in current limiting mode - which means you've overloaded it and are just asking for trouble.
That's not true at all. If you run 5 36v cobs in parallel on a CV driver that puts out 36v and 2.1a, you get 420ma per cob. If one of those cobs fails, that 2.1a is now running through 4 cobs, still at 36v, meaning your 4 cobs are now running at 525ma. This is basic math man.
It may be basic math, but it ISNT basic semiconductor physics - or even ohms law. The current through a junction is determined by the voltage applied. Nothing else (temperature excepted). The action you describe ONLY occurs with a Constant Current power supply, because the CC supply adjusts its voltage UPWARD to maintain current flow..
it is impossible for cobs to run at both 420 mA and 525 mA and still be 36V. it can only operate on the curve (thermal droop excluded)
For sure, I just threw out those numbers for an example.
so you threw out two wrong numbers deliberately?
Thinking about it more, you're totally right. Apologies man, I was a few beers deep last night.
