Quick question on which HLG600 to use.

Airwalker16

Well-Known Member
Hello I have a quick question. I think that I finally have these drivers figured out but want to make sure. I have found some strips that are 49 volts and are recommended to run at 700 milliamp. So if I wanted to run 25 of them on an hlg 600, I think that my math tells me I would want the HLG-36A which provides 16.7 amps. Is this correct?

Also, does this mean that when this driver is running these strips, that 16.7 amps will always be running through my outlet!? I wired them for 20amp but I assume a lot of US users are running small runs using 600watt lights EASY on 15A breakers.
 

nfhiggs

Well-Known Member
Hello I have a quick question. I think that I finally have these drivers figured out but want to make sure. I have found some strips that are 49 volts and are recommended to run at 700 milliamp. So if I wanted to run 25 of them on an hlg 600, I think that my math tells me I would want the HLG-36A which provides 16.7 amps. Is this correct?

Also, does this mean that when this driver is running these strips, that 16.7 amps will always be running through my outlet!? I wired them for 20amp but I assume a lot of US users are running small runs using 600watt lights EASY on 15A breakers.
No. The 36A is only 36 volts and you need 49 volts. You need the HLG-600H-48A, which will run 25 strips at a little less than 500 mA each.

A 600W driver will pull under 6 amps at the wall.
 

Airwalker16

Well-Known Member
No. The 36A is only 36 volts and you need 49 volts. You need the HLG-600H-48A, which will run 25 strips at a little less than 500 mA each.

A 600W driver will pull under 6 amps at the wall.
But I want to run them at 700MA, so is that just not possible with the HLG-600 model? Because I could have sworn that you didn't have to match the forward voltage of your chips/cobs/boards with the number at the end of the driver...
 

nfhiggs

Well-Known Member
But I want to run them at 700MA, so is that just not possible with the HLG-600 model?
Not possible with a 600W supply. 49V times 0.7 amps is 34.3 watts per strip. 34.3 times 25 is 857 watts total. You need to use two HLG-480H-48A power supplies if you want to run them at that current level. Either keep one strip as a spare, or get one more to even it out.

Because I could have sworn that you didn't have to match the forward voltage of your chips/cobs/boards with the number at the end of the driver...
Thats true only of the Constant Current power supplies - the CV power supplies have to match the voltage of the load to the voltage output of the supply, which in this case is indicated by the last number group.
 

OLD MOTHER SATIVA

Well-Known Member
Then you use two 36V supplies connected in series. Or just use a CC supply. Unfortunately the 600W HLG's do not come in CC versions.
hook up 36 v drivers in series..??<----

then...74 vf cobs in parallel?

[have never hooked up two drivers together yet either way]

panels/cobs of course yes
 
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nfhiggs

Well-Known Member
hook up 36 v drivers in series..??<----

then...74 vf cobs in parallel?

[have never hooked up two drivers together yet either way]

panels/cobs of course yes
Yup. The positive output wire from the first driver is connected to the negative output wire of the second driver. Load is then connected to the negative output of the first driver, and the positive output of the second driver. Its just like placing batteries in series.
 

Airwalker16

Well-Known Member
Yup. The positive output wire from the first driver is connected to the negative output wire of the second driver. Load is then connected to the negative output of the first driver, and the positive output of the second driver. Its just like placing batteries in series.
Explain this a bit more in detail?
 

Airwalker16

Well-Known Member
There ya go - Except the 72v COBs would be in parallel.
As in the pos and negs would go to each cob rather than connecting end to end.
I.e. bottom drivers positive would come up to the top cob and using say an ideal chip lok holder, would go in one hole, and pos again on the other hole, connected to the next cob holder. Same with negatives and so on and so forth.
Right?

Or would it be a line from the bottom drivers positive, split into 4 lines going to each pos? And same with neg?
 

Aolelon

Well-Known Member
Either way would work. They are essentially the same thing, just different ways of using the wires to connect them, personally I think number 1 would be easier, as you said you're using ideal holders. I'm not 100% sure you could fit two wires into one holder slot. But I've never used one so. Or you could connect them like 2, and just a wire coming out of the first cob (where the driver attatches) and use both a wago to connect the driver wire, and the wire going to the cobs.
 
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Airwalker16

Well-Known Member
Either way would work. They are essentially the same thing, just different ways of using the wires to connect them, personally I think number 1 would be easier, as you said you're using ideal holders. I'm not 100% sure you could fit two wires into one holder slot. But I've never used one so. Or you could connect them like 2, and just a wire coming out of the first cob (where the driver attatches) and use both a wago to connect the driver wire, and the wire going to the cobs.
Chip Lok ideal holders have 2 poke in holes on each polarity.

image.png
 
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