Because more photons, but not more energy? I swear I keep saying the same thing, if I'm wrong someone correct me lol.
I think the way it works is that a high energy (hv) blue photon hits and electron and pushes it to higher energy state. Now some of this energy (E) is lost in molecular vibrations what i do not completely understand. So now electron jumps back to default state and emits a lower energy (hv-E) red/yellow photon.I thought we were absorbing photons, then using the energy to create new photons. The only limit should be the amount of energy.
how does that relate to photosynthesis. 630 vs 660, etc?
Yes and Goud is not helpingSome of this stuff gives me a headache trying to understand.
ok i will read Alesh's post again.what is the QER of a white Cob?
Well no, that makes total sense to me, but I guess I'm wondering if the energy lost in conversion has any relationship with the distance shifted.
So photoluminescence, phosphorescence, and fluorescence, so we're not actually absorbing the photon energy as I was thinking, we're squishing the wave and robbing energy from the blue or uv photon?
Google never gives me a straight answer, what happened to Jeeves?
So the question lays around now at what is the current blue die efficiency at the ~100ma they are ran. And then we can see what the current level of phosphor loss on say a 3590 is.
according to the Cree PCT the Xte royalblau (25°C -/- 100mA), the highest bin reaches 72%
phosphor loss is about 15% for high CCT and low CRI., and goes down to 35% for lower CCT and higher CRI.
View attachment 3702768 for royal blue and photo red Lumen is here milli Watt!
Is that mw/watt?
That's kinda what I was getting at. As I still ponder can I hit the phosphor with x photons in any nm and get more photons out as in numerically? Just curiosity lol. Is it possible or is that the limitation of the phosphor itself. As much as I do understand some of this it still leaves me wanting to understand the exact reactions that take place inside the phosphor. It may be a question similar to "how many licks does it take to get to the center of a tootsie pop?" Crunch the world may never know lol.
Because more photons, but not more energy? I swear I keep saying the same thing, if I'm wrong someone please correct me lol.
That's kinda what I was getting at. As I still ponder can I hit the phosphor with x photons in any nm and get more photons out as in numerically? Just curiosity lol. Is it possible or is that the limitation of the phosphor itself. As much as I do understand some of this it still leaves me wanting to understand the exact reactions that take place inside the phosphor. It may be a question similar to "how many licks does it take to get to the center of a tootsie pop?" Crunch the world may never know lol.
Thats an easy one.its 3 licks,ah 1, ah 2, ah 3. Three lol.alot of the younger crowd here wont get that![]()