johnny be good Active Member Oct 21, 2010 #1 looking for some good clones. If you have any extra clones or plants. let me know if you can help me, I am a MI card holder.
looking for some good clones. If you have any extra clones or plants. let me know if you can help me, I am a MI card holder.
rzza Well-Known Member Oct 21, 2010 #2 with your hard card? if so i could help ya out. what area are you in?
johnny be good Active Member Oct 21, 2010 #3 yeah just got it in the mail last week. Im in the capital city. strains/prices(lower the better) clones or seeds
yeah just got it in the mail last week. Im in the capital city. strains/prices(lower the better) clones or seeds
kindone Active Member Oct 21, 2010 #4 I got 2 extra OG kush clones in rockwool, should have roots within a couple of days, might be interested in a trade for meds . Here is pic from last saturday when I took them.
I got 2 extra OG kush clones in rockwool, should have roots within a couple of days, might be interested in a trade for meds . Here is pic from last saturday when I took them.
rzza Well-Known Member Oct 21, 2010 #5 sharksbreath la woman qwerkle sleestack lsd burmese kush cuttings only, i dont have the plant limit to root them. $5 each. you would have to come to farmington hills though.
sharksbreath la woman qwerkle sleestack lsd burmese kush cuttings only, i dont have the plant limit to root them. $5 each. you would have to come to farmington hills though.
streets Well-Known Member Oct 22, 2010 #7 rzza said: sharksbreath la woman qwerkle sleestack lsd burmese kush cuttings only, i dont have the plant limit to root them. $5 each. you would have to come to farmington hills though. Click to expand... I am INTERESTED!! I have a hard card.. PM me and lets meet up this weekend.
rzza said: sharksbreath la woman qwerkle sleestack lsd burmese kush cuttings only, i dont have the plant limit to root them. $5 each. you would have to come to farmington hills though. Click to expand... I am INTERESTED!! I have a hard card.. PM me and lets meet up this weekend.