M\W xlg-240h-AB how to dim ?

horribleherk

Well-Known Member
I'm ordering 2 of these from jameco.com cob kits is out of dimmers & they offer the 50k that is supposed to dim 2 drivers I'm really wanting to dim these what will work ??? & where do you find it ? don't care if its a dimmer for each driver or not as long as it works people have coached me so far & thanks in advance
 

cobshopgrow

Well-Known Member
you maybe can order some 100K linear potentiometers ,dim one driver, or 50K dim 2 driver with your order.
best would be if they really reach 100k = 100% light output, order some more and test them with a multimeter.
 

horribleherk

Well-Known Member
Thanks for the reply I'm new at this so if I use one 100k per driver I'll get all the power when turned all the way up? cob kits is out of both 50k & 100k
 

horribleherk

Well-Known Member
To ensure you get all dat juice, wire a 10K resistor in line on the positive lead.
Before the potentiometer or after? gotta remember I'm new at this ! when the parts get here I'll have a better understanding its for the hack I'm doing that's finally materializing
 

Airwalker16

Well-Known Member
Before the potentiometer or after? gotta remember I'm new at this ! when the parts get here I'll have a better understanding its for the hack I'm doing that's finally materializing
Lol. Think about what you just said.
There's a pot with 3 poles. You will use the middle for positive and negative to whatever side you want to turn the knob to dim to 0.
If there's a resistor on the positive lead as I said, how else could you wire it? You can only put the resistor in 2 places really. On the neg or pos lead. Just throw it on the positive. Lol. That was funny.
 

diyled

Well-Known Member
Lol. Think about what you just said.
There's a pot with 3 poles. You will use the middle for positive and negative to whatever side you want to turn the knob to dim to 0.
If there's a resistor on the positive lead as I said, how else could you wire it? You can only put the resistor in 2 places really. On the neg or pos lead. Just throw it on the positive. Lol. That was funny.
You know thats incorrect, probably not, as you most likely just googled it. Consistent bad advise.
 

cobshopgrow

Well-Known Member
Thanks for the reply I'm new at this so if I use one 100k per driver I'll get all the power when turned all the way up? cob kits is out of both 50k & 100k
yep, one 100k for one driver and youre fine.
these potentiometers do have variance, for 100% youll need at least 100k resistance.
you can put a resistor in line to asure there is enough resistance.

if you have a cheap multimeter you can simply test and see, its no rocket science.
 

Airwalker16

Well-Known Member
yep, one 100k for one driver and youre fine.
these potentiometers do have variance, for 100% youll need at least 100k resistance.
you can put a resistor in line to asure there is enough resistance.

if you have a cheap multimeter you can simply test and see, its no rocket science.
I guess you're wrong too. @diyled likes to say we're wrong at least
 

Airwalker16

Well-Known Member
You know thats incorrect, probably not, as you most likely just googled it. Consistent bad advise.
Well you can tell that to every person I've ever asked about potentiometer wiring.
Instead of being a shade throwing chump, why don't you EDUCATE US with the correct answer hmmmmm? I'm sick of your Shit.
I've been on this forum a lot longer than you. And I was one of the pioneers of the first heatsinkUSA/COB builds. I miss those days. People were so much cooler then...
I've word up all my single driver pots this way and have asked on the forum for confirmation that it was correct.
Guess you can blame @Rahz @Randomblame and the entire 3-in-1 dimming thread!
 
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Rocket Soul

Well-Known Member
Calm down everybody. I do believe ive had knowledgeable people around (randomblame, god bless him) here recing using 110kohm, to get at that little bit of extra current in meanwell drivers. But then again i dont know what this does to driver longevity
 

Airwalker16

Well-Known Member
Calm down everybody. I do believe ive had knowledgeable people around (randomblame, god bless him) here recing using 110kohm, to get at that little bit of extra current in meanwell drivers. But then again i dont know what this does to driver longevity
Wasn't aware they made a 110k ohm potentiometer.
 

Airwalker16

Well-Known Member
100k ohm poti plus 10k ohm in series.

But the AB driver should have internal dimming as well. I think someone said the screwdriver hole is underneath, on the bottom. Not sure.
That's correct. It's on da bottom. Probably the driver is screwed down to the fixture and hadn't thought to check underneath because, why would you, is my guess? I still don't understand why the hell they would make the driver like that. It's so stupid and user UNfriendly.

Edit: he wants to order them but couldn't see any plug for a screwdriver. I guess I was half right.
 

horribleherk

Well-Known Member
yep, one 100k for one driver and youre fine.
these potentiometers do have variance, for 100% youll need at least 100k resistance.
you can put a resistor in line to asure there is enough resistance.

if you have a cheap multimeter you can simply test and see, its no rocket science.
thanks I have a multimeter
 

horribleherk

Well-Known Member
yep, one 100k for one driver and youre fine.
these potentiometers do have variance, for 100% youll need at least 100k resistance.
you can put a resistor in line to asure there is enough resistance.

if you have a cheap multimeter you can simply test and see, its no rocket science.
The light is together I found a deal on two hlg240h-54 b drivers & cob kits once again has 100k dimmers in stock I'm finishing my current grow with the lightIMG_20200409_154059.jpgIMG_20200409_154219.jpgIMG_20200409_154307.jpgIMG_20200409_154510.jpg
 
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