I don't think it's an outlier Buck. Maybe. We'll see.
but go ahead and cling to one outlier poll by quinnipiac. don't say i didn't warn you about your own stupidity and inability to read simple polling data.
it's one poll that cntradicts what every single other poll says, retard.I don't think it's an outlier Buck. Maybe. We'll see.
And it was a recent poll.it's one poll that cntradicts what every single other poll says, retard.
Face it Buck. It's Jeb or Bernie.
be stupid somewhere else.
until other polls confirm its findings, it is an outlier and to be treated as such.And it was a recent poll.
Could you really pass an actuarial exam Buck?until other polls confirm its findings, it is an outlier and to be treated as such.
you're welcome for the lesson in math and statistics, courtesy of an ASU dropout.
yes.Could you really pass an actuarial exam Buck?
Don't you have to hold a degree in order to sit for the exam?yes.
tell me again about how nature has intent, which you claimed you learned in college.
no.Don't you have to hold a degree in order to sit for the exam?
Then why don't you take the actuarial exam and prove you can pass it? I offered to pay for the exam and your time a while ago. The offer still stands. Come to my house, since you know where I live, and I'll give you the money. And feed you some damn fine BBQ and cannabis.no.
tell me again about how nature has intent, which you claimed you learned in college.
unlike rend pawl, i do not accept money from white supremacists.Then why don't you take the actuarial exam and prove you can pass it? I offered to pay for the exam and your time a while ago. The offer still stands. Come to my house, since you know where I live, and I'll give you the money. And feed you some damn fine BBQ and cannabis.
An insurance company determines that N, the number of claims received in a week, is a random variable with P[N = n] = 1/2n+1, where n > 0 . The company also determines that the number of claims received in a given week is independent of the number of claims received in any other week. Determine the probability that exactly seven claims will be received during a given two week period.unlike rend pawl, i do not accept money from white supremacists.
i have nothing to prove. go fetch me a sample question and i'll answer it.
You lose Buck. I posted a sample question, and it scared you off.unlike rend pawl, i do not accept money from white supremacists.
i have nothing to prove. go fetch me a sample question and i'll answer it.
can't you even format the question right so i stand a chance?An insurance company determines that N, the number of claims received in a week, is a random variable with P[N = n] = 1/2n+1, where n > 0 . The company also determines that the number of claims received in a given week is independent of the number of claims received in any other week. Determine the probability that exactly seven claims will be received during a given two week period.
You have 3 minutes to post the answer.
Yeah, you took a long time to look that up on the internet.can't you even format the question right so i stand a chance?
you should have typed 1/(2^(n+1)) so i would know what you are talking about.
in which case P[N=7] = summation from 0 to 7 of N1 (week 1) and N2 (week 2).
sum up all the probabilities of week 1 from 0 to 7 then sum up all the probabilities of week 2 using 7-n (because we need exactly 7).
you get the summation from n=0 to 7 of (1/(2^(n+1))) * (1/(2^(8-n)))
the n's cancel out, leaving you with the summation from 0 to 7 of 1/(2^9) = 8/(2^9) = 8/512 = 1/64
excuse me for going out and fetching dinner for my wife and i.
i went downtown to get bourbon grill for the wife and i.Yeah, you took a long time to look that up on the internet.
And with your search skills, that was an eternity.
If you're really smart and knowledgeable enough to answer that question in so little time, then why did you quit college? It just don't make any sense.i went downtown to get bourbon grill for the wife and i.